Theorem: 1 = 1/2:
Proof:
We can re-write the infinite series 1/(1*3) + 1/(3*5) + 1/(5*7) + 1/(7*9)
+…
as 1/2((1/1 – 1/3) + (1/3 – 1/5) + (1/5 – 1/7) + (1/7 – 1/9) + … ).
All terms after 1/1 cancel, so that the sum is 1/2.
We can also re-write the series as (1/1 – 2/3) + (2/3 – 3/5) + (3/5 – 4/7)
+ (4/7 – 5/9) + …
All terms after 1/1 cancel, so that the sum is 1.
Thus 1/2 = 1.
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Hello, this is probably 438-9012, yes, the house of the famous statistician. I’m probably not at home, or not wanting to answer the phone, most probably the latter, according to my latest calculations. Supposing that the universe doesn’t end in the next 30 seconds, the odds of which I’m still trying to calculate, you can leave your name, phone number, and message, and I’ll probably phone you back. So far the probability of that is about 0.645. Have a nice day.
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Theorem: e=1
Proof:
2*e = f
2^(2*pi*i)e^(2*pi*i) = f^(2*pi*i)
e^(2*pi*i) = 1
Therefore:
2^(2*pi*i) = f^(2*pi*i)
2=f
Thus:
e=1
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It is proven that the celebration of birthdays is healthy. Statistics show that those people who celebrate the most birthdays become the oldest. — S. den Hartog, Ph D. Thesis Universtity of Groningen.
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Theorem: 1 = -1
Proof:
1 = sqrt(1) = sqrt(-1 * -1) = sqrt(-1) * sqrt(-1) = 1^ = -1
Also one can disprove the axiom that things equal to the same thing are equal to each other.
1 = sqrt(1)
-1 = sqrt(1)
Therefore 1 = -1
As an alternative method for solving:
Theorem: 1 = -1
Proof:
x=1
x^2=x
x^2-1=x-1
(x+1)(x-1)=(x-1)
(x+1)=(x-1)/(x-1)
x+1=1
x=0
0=1
=> 0/0=1/1=1
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